我是靠谱客的博主 年轻香氛,这篇文章主要介绍314 - Robot(用Dijkstra怎么还ac不了),现在分享给大家,希望可以做个参考。

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#include <cstdio> #include <cstring> #include <queue> #include <string> using namespace std; const int N = 55; const int M = 4; const int dx[] = {-1, 0, 1, 0}; const int dy[] = {0, 1, 0, -1}; const int INF = 0x3f3f3f3f; struct HeapNode { int x, y, d, dir; bool operator < (const HeapNode &other) const { return d > other.d; } }; int n, m; bool vis[M][N][N]; int grid[N][N]; int curdir; int srcx, srcy, dstx, dsty; char buf[N]; int d[M][N][N]; int main() { #ifndef ONLINE_JUDGE freopen("e:\uva_in.txt", "r", stdin); #endif while (scanf("%d%d", &m, &n) == 2 && (n || m)) { memset(grid, 0x00, sizeof(grid)); for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { scanf("%d", &grid[i][j]); } } for (int i = m - 1; i >= 0; i--) { for (int j = n - 1; j >= 0; j--) { if (grid[i][j]) { grid[i + 1][j] = grid[i][j + 1] = grid[i + 1][j + 1] = 1; } } } scanf("%d%d%d%d%s", &srcx, &srcy, &dstx, &dsty, buf); string s = buf; if (s == "north") curdir = 0; else if (s == "east") curdir = 1; else if (s == "south") curdir = 2; else curdir = 3; //printf("srcx=%d, srcy=%d, dstx=%d, dsty=%d, curdir=%dn", srcx, srcy, dstx, dsty, curdir); if (grid[srcx][srcy] || grid[dstx][dsty]) { printf("-1n"); continue; } if (srcx < 0 || srcx >= m || srcy < 0 || srcy >= n) { printf("-1n"); continue; } if (dstx < 0 || dstx >= m || dsty < 0 || dsty >= n) { printf("-1n"); continue; } priority_queue<HeapNode> q; HeapNode node; bool found = false; node.x = srcx, node.y = srcy, node.d = 0, node.dir = curdir; q.push(node); memset(d, 0x3f, sizeof(d)); d[curdir][srcx][srcy] = 0; memset(vis, false, sizeof(vis)); while (!q.empty()) { HeapNode tmp = q.top(); q.pop(); int curx = tmp.x, cury = tmp.y; int curdir = tmp.dir; //printf("curx=%d, cury=%d, curdir=%d, d=%dn", curx, cury, curdir, tmp.d); if (curx == dstx && cury == dsty) { found = true; printf("%dn", tmp.d); break; } if (vis[curdir][curx][cury]) continue; vis[curdir][curx][cury] = true; int newDir = (curdir + 1) % 4; int x = curx, y = cury; if (d[curdir][curx][cury] + 1 < d[newDir][curx][cury]) { d[newDir][curx][cury] = d[curdir][curx][cury] + 1; node.x = x, node.y = y, node.dir = newDir, node.d = d[newDir][curx][cury]; q.push(node); } newDir = (curdir + 3) % 4; x = curx, y = cury; if (d[curdir][curx][cury] + 1 < d[newDir][curx][cury]) { d[newDir][curx][cury] = d[curdir][curx][cury] + 1; node.x = x, node.y = y, node.dir = newDir, node.d = d[newDir][curx][cury]; q.push(node); } newDir = curdir; for (int i = 1; i <= 3; i++) { x = curx + dx[curdir] * i; y = cury + dy[curdir] * i; if (x < 0 || x >= m || y < 0 || y >= n) break; if (grid[x][y]) break; if (d[curdir][curx][cury] + 1 < d[newDir][x][y]) { d[newDir][x][y] = d[curdir][curx][cury] + 1; node.x = x, node.y = y, node.dir = newDir, node.d = d[newDir][x][y]; q.push(node); } } } if (!found) { printf("-1n"); } } return 0; }

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