我正在设置一个按钮的可见性,如下所示:
public Bundle setActivityState(Bundle bundle){
startBtn = (Button) findViewById(R.id.startSensorsBtn);
startBtn.setVisibility(
getVisibilityState(bundle,PersistanceConstants.START_BTN_STATE)
);
return bundle;
}
public int getVisibilityState(Bundle bundle,String keyName){
if (bundle.getInt(keyName) == View.VISIBLE){
return View.VISIBLE;
} else if (bundle.getInt(keyName) == View.INVISIBLE){
return View.INVISIBLE;
} else if (bundle.getInt(keyName) == View.GONE){
return View.GONE;
}
return 0;
}
但我收到错误:
Must be one of: View.VISIBLE,View.INVISIBLE,View.GONE less... (Ctrl+F1)
Reports two types of problems:
- Supplying the wrong type of resource identifier. For example,when calling Resources.getString(int id),you should be passing R.string.something,not R.drawable.something.
- Passing the wrong constant to a method which expects one of a specific set of constants. For example,when calling View#setLayoutDirection,the parameter must be android.view.View.LAYOUT_DIRECTION_LTR or android.view.View.LAYOUT_DIRECTION_RTL.
而打电话
getVisibilityState(bundle,PersistanceConstants.START_BTN_STATE)
我不知道如何解决这个问题.我明白,它期待一组给定的值,但我知道的只是传递一个int.这里可以做些什么?
最后
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