杭电oj2055

Problem Description
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, … f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

Output
for each case, you should the result of y+f(x) on a line.

Sample Input
6
R 1
P 2
G 3
r 1
p 2
g 3

Sample Output
19
18
10
-17
-14
-4

AC代码：

#include <stdio.h>
#include <iostream>
using namespace std;
int f(char x) {
	if (x >= 'a'&&x <= 'z') {   //a~z = -1~-26 ASCII:a=97
		return -(x - 96);
	}
	if (x >= 'A'&&x <= 'Z') {    //A~Z = 1~26 ASCII:A=65
		return x - 64;      
	}
}
int main() {
	int t, y;
	char x;
	cin >> t;
	while (t--) {
		cin >> x >> y;
		int k = f(x) + y;
		cout << k << endl;
	}
	return 0;
}

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