Problem C: day-of-year

#include <stdio.h>
int day_of_year(int month, int day, int year);
int main()
{
    int m, d, y;
    while (scanf("%d %d %d", &m, &d, &y) != EOF)
    {
        printf("%dn", day_of_year(m, d, y));
    }
    return 0;
}
/* 你的代码将被嵌在这里 */

int day_of_year(int month, int day, int year)

{

    int p[4]={31,28,29,30},i,sum=0;

    for(i=1;i<month;i++)

    {

        if(i==2&&year%4==0)

        sum+=p[2];

        else if(i==2&&year%4!=0)

        sum+=p[1];

        else if(i%2!=0&&i!=2&&i<=7)

        sum+=p[0];

        else if(i%2==0&&i!=2&&i<8)

        sum+=p[3];

        else if(i%2==0&&i>=8)

        sum+=p[0];

        else if(i%2!=0&&i>8)

        sum+=p[3];

}

return sum+=day;

}

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