展开泰勒公式，求精度

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我是靠谱客的博主拼搏曲奇，这篇文章主要介绍展开泰勒公式，求精度，现在分享给大家，希望可以做个参考。

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#include "stdafx.h"
#include <iostream>
#include <stdlib.h>
using namespace std;
double one(double x, double n);
int _tmain(int argc, _TCHAR* argv[])
{
double x;
double n;
cout << "请输入x的值：" << endl;
cin >> x;
cout << "请输入n的值：" << endl;
cin >> n;
double youzhi = 0;
for (double i = 0; i <= n;i++)
{
if (n == 0)
{
youzhi = 1;
break;
}
else
youzhi += one(x, i);
}
if (n!=0)
{
youzhi = youzhi + 1;//等式右边加数不为0时，加上1
}
double zuozhi = exp(x);
double errorrate = (zuozhi - youzhi) / zuozhi;
cout << "误差率： " << fabs(errorrate) * 100 << "%" << endl;
system("pause");
return 0;
}
/*求等式右边单个值，忽略首项*/
double one(double x, double n)
{
double nResult = 1;
for (double i = 1; i <= n;i++)
{
nResult *= x / i;
}
return nResult;
}